-4.9x^2+9.2x+9=0

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Solution for -4.9x^2+9.2x+9=0 equation:



-4.9x^2+9.2x+9=0
a = -4.9; b = 9.2; c = +9;
Δ = b2-4ac
Δ = 9.22-4·(-4.9)·9
Δ = 261.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.2)-\sqrt{261.04}}{2*-4.9}=\frac{-9.2-\sqrt{261.04}}{-9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.2)+\sqrt{261.04}}{2*-4.9}=\frac{-9.2+\sqrt{261.04}}{-9.8} $

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